When sliding a marker across the lab table to a fellow physics student, a studen

Question

When sliding a marker across the lab table to a fellow physics student, a student misses and accidentally slides the marker horizontally off the table. The marker lands 2.2 meters horizontally from the edge of the table. The lab table is 1-m high. Ignoring air resistance, answer the following questions.

a. How long was the marker in the air?

b. What was the initial velocity of the marker just after leaving the table?

c. What was the magnitude and direction of the velocity of the marker just before hitting the floor?

Thanks.

Explanation / Answer

(a)

The time to travel the marker in air is

t = sqrt 2h/g = sqrt 2(1.0 m)/ 9.8 m/s^2 = 0.45 s

(b)

From the range equation

R = Ut

U = R/t = 2.2 m/0.45 s = 4.86 m/s

(c)

The magnitide of velocity is

v = sqrt U^2 + g^2 t^2 = sqrt ( 4.86 m/s)^2 + ( 9.8 m/s)^2 ( 0.45 s)^2 = 6.56 m/s

direction is

theata = tan^-1 (gt/u) = tan^-1 ( 9.8 m/s^2) ( 0.45 s)/ 4.86 m/s = 42.22 degree

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