A massless rope that passes over a frictionless pulley connects two blocks. The

Question

A massless rope that passes over a frictionless pulley connects two blocks. The mass of the block on the left is 10 kg, and it rests on a plane making an angle of 40 degrees with respect to the horizontal. The block and the slope interact with "Mu" static = 0.6 and "Mu kinetic = 0.15. The block on the right rests on a plane making an angle of 30 degrees with respect to the horizontal. This block and slope interact with "Mu" static = 0.3 and "Mu" kinetic = 0.10. The system starts at rest.

What is the minimum mass of the right side block if the system is to move to the right?

Explanation / Answer

to move let mass be M
and M to be minimum that means a= 0

M*9.8*sin 30 - T - (M*9.8*cos30*0.1) = 0

T - (10*9.8*sin40) - (10*9.8*cos40*0.15) = 0

a = 1.5009 m/s^2

M =18.33 kg

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