I got this question wrong so please help me solve both parts. Correct answer is

Question

I got this question wrong so please help me solve both parts. Correct answer is shown but id like to know how to get there. Thanks!

A rod of length 53.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod. The string on side B is cut. Find the magnitude of the initial acceleration of end B. The string on side B is retied and now has only half the length of the string on side A. Find the magnitude of the initial acceleration of the end B when the string is cut.

Explanation / Answer

W = (1.4*9.8 = 13.72 N

net torque about A = 0

Tb*L = W*(L/2)

Tb = W/2 = 6.86 N

if b breaks

W*(L/2)= I*alfa

W/2 = (1/3)*m*L^2*a/L

a = W*3/m = (6.86*3)/1.4 = 1.47*10^1 m/s^2

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