1. A pair of charged conducting plates produces a uniform field of 12,000 N/C di

Question

1. A pair of charged conducting plates produces a uniform field of 12,000 N/C directed to the right, between the plates. The separation of the plates is 40 mm. In the figure, an ELECTRON is projected from plate A, directly toward plate B, with an initial speed of v0 = 2.0 x 10^7 m/s. The speed of the electron as it strikes plate B is?

2. A pair of charged conducting plates produces a uniform field of 12,000 N/C, between the plates, directed from positive plate A to negative plate B The separation of the plates is 40 mm. A PROTON is projected from plate A with a slow initial speed of v0 = 0 m/s. it accelerates towards plate B. The speed of the proton as it strikes plate B is ____?

PLEASE PLEASE HELP AND GIVE DETAILED STEP BY STEP INSTRUCTIONS. I have tried so many times PLEASE HELLLLLP!!!

Explanation / Answer

Given,

Field = 12000 N/C

Distance bt plates = s = 40mm =.04m

intial vel of e = u = 2.0 x 107 m/s

The acceleration will be given by

a = F / m = qE/m = 12000 N/C x - 1.6x10-19C / 9.1 x10-31 m/s2
a = -2.1 x 1015 m/s2

v2 - u2 = 2 x a x s, u is initial velocity and v is final, So Fival velocity will be given by,

v = sqrt (u2 + 2 x a x s ) = sqrt { (2.0 x 107 )2 + 2(-2.1 x 1015 ) x 0.04)}

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