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1. A net force of 3.50 N acts on a 2.75 kg object. What is the acceleration of t

ID: 1281339 • Letter: 1

Question

1.     A net force of 3.50 N acts on a 2.75 kg object. What is the acceleration of the object?

2.     Describe the basic concept of Atwood machine. What is the net applied force? What is the mass to which this net force is applied?

3.     An Atwood machine consists of a 1.06000kg mass and a 1.000-kg mass connected by a string over a massless and frictionless pulley. What is the acceleration of the system? Assume g is 9.80 m/s.

4.     Suppose the system in the question 3 has a frictional force of 0.056 N. What is the acceleration of the system?

5.     Suppose the frictionless system described in question 3 is released from rest at t=0. How long does it take for the large mass to fall 1.2000 m?



6.     Suppose the system with friction described in question 2 is released from the rest at t=0. How long does it take for the large mass to fall 1.200 m?

Explanation / Answer

1) Fnet = m a

a = Fnet/m = 3.5/2.75= 1.27 m/s^2

2)the net force is the difference between the two weights

it is applied to the heavier mass

3)

Fnet = m a

0.06*9.81 = (2.06)*a

a=0.286 m/s^2

4)

now 0.06*9.81 - 0.056 = 2.06*a

a=0.259 m/s^2

5)

y = v0t + 1/2 a t^2

1.2 = 0.5*0.286*t^2

t=2.90 s

6) do you mean part 4?

then 1.2 = 0.5*0.259*t^2
t=3.04 s