(I keep getting the answer incorrect please help) The 2.3-cm-diameter solenoid i
ID: 1321696 • Letter: #
Question
(I keep getting the answer incorrect please help)
The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a
6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.40T .
1.) What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express two sig figs
Flux= _______________Wb
2.) What is the magnetic flux through the loop when it is tilted at a 60? angle? express two sig figs
flux=____________Wb
The 2.3-cm-diameter solenoid in (Figure 1) passes through the center of a 6.0-cm-diameter loop. The magnetic field inside the solenoid is 0.40T . 1.) What is the magnetic flux through the loop when it is perpendicular to the solenoid? Express two sig figs Flux= _______________Wb 2.) What is the magnetic flux through the loop when it is tilted at a 60? angle? express two sig figs flux=____________WbExplanation / Answer
The diameter of the solenoid d = 2.3cm
then the radius of the solenoid r = 1.15cm
the magnetic filed B = 0.40T
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PART-A
The magnetic flux through the loop:
flux=(magnetic field)(area)(costheta)
phi = BAcos(theta)
phi = 0.40*pi*(1.15*10^-2)^2 *1
flux = 1.661*10^-4 wb
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PART-B
when it is tilted at theta = 60
flux=(magnetic field)(area)(costheta)
fux = 0.40*pi*(1.15*10^-2)^2 *cos60
flux= 8.309*10^-5 wb
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