The circuit shown has the following values: R = 60 ohms, voltmeter resistance =

Question

The circuit shown has the following values: R = 60 ohms, voltmeter resistance = 300ohms, ammeter reading = 0.60 A.

1)What will the voltmeter reading be? (Hint 1: The current through the resistor plus the current through the volmeter must be equal to the current through the ammeter. Hint 2: The resistor R is in parallel with the voltmeter. How do you find the effective resistance of two resistors in parallel?)

2)What is the current through the voltmeter?

3)What is the current through R?

4)If the voltmeter current is neglected and the 0.60 amps shown by the ammeter is assumed to be flowing only through R, what value would one abtain for the resistance of R?

5) What percent error in the experimental value of R results if the procedure in question 9 is followed?

The circuit shown has the following values: R = 60 ohms, voltmeter resistance = 300 ohms, ammeter reading = 0.60 A. 1)What will the voltmeter reading be? (Hint 1: The current through the resistor plus the current through the volmeter must be equal to the current through the ammeter. Hint 2: The resistor R is in parallel with the voltmeter. How do you find the effective resistance of two resistors in parallel?) 2)What is the current through the voltmeter? 3)What is the current through R? 4)If the voltmeter current is neglected and the 0.60 amps shown by the ammeter is assumed to be flowing only through R, what value would one abtain for the resistance of R? 5) What percent error in the experimental value of R results if the procedure in question 9 is followed?

Explanation / Answer

Current through voltmeter = 0.6 * 60/360 =0.1 A (ans)

So voltmeter reading = current through 60 ohm = 0.6 -0.1 =0.5 *60 =30 V (ans)

Current through R = 0.6 -0.1 =0.5 A (ans)

Resistance = V/I = 30/0.6 = 50 ohm (ans)

Percent error = 60 -50/60 *100 = 16.67 % (ans)

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