Given the circuit above, the instant that the switch is closed, the voltage acro

Question

Given the circuit above, the instant that the switch is closed, the voltage across the capacitor is:

0.0 V

3.0 V

1.5 V

.75 V

Given the circuit above, the instant that the switch is closed, the voltage across the resistor is:

3.0 V

.75 V

1.5 V

0.0 V

Given the circuit above, a long time after the switch is closed, the voltage across the capacitor is:

.75 V

3.0 V

0.0 V

1.5 V

Given the circuit above, a long time after the switch is closed, the voltage across the resistor is:

0.0 V

3.0 V

1.5 V

.75 V

How long does it take the voltage across the capacitor to increase to 63% of its maximum value?

1.1 ms

44 ms

.023 ms

1.7 ms

0.0 V

3.0 V

1.5 V

.75 V

Given the circuit above, the instant that the switch is closed, the voltage across the resistor is:

3.0 V

.75 V

1.5 V

0.0 V

Given the circuit above, a long time after the switch is closed, the voltage across the capacitor is:

.75 V

3.0 V

0.0 V

1.5 V

Given the circuit above, a long time after the switch is closed, the voltage across the resistor is:

0.0 V

3.0 V

1.5 V

.75 V

How long does it take the voltage across the capacitor to increase to 63% of its maximum value?

1.1 ms

44 ms

.023 ms

1.7 ms

RC Time Constant: Given the circuit above, the instant that the switch is closed, the voltage across the capacitor is: 0.0 V 3.0 V 1.5 V .75 V Given the circuit above, the instant that the switch is closed, the voltage across the resistor is: 3.0 V .75 V 1.5 V 0.0 V Given the circuit above, a long time after the switch is closed, the voltage across the capacitor is: .75 V 3.0 V 0.0 V 1.5 V Given the circuit above, a long time after the switch is closed, the voltage across the resistor is: 0.0 V 3.0 V 1.5 V .75 V How long does it take the voltage across the capacitor to increase to 63% of its maximum value? 1.1 ms 44 ms .023 ms 1.7 ms

Explanation / Answer

1) 0.0 V (ans) ( When switch is closed , the capacitor behaves as short circuit so no voltage across it.)

2)1.5 V (ans) ( Since therer is no voltage across the capacitor, SO all the voltage will be across the resistor)

3)1.5 V (ans) ( After a lon time the capacitor gets fully charged)

4)0.0            ( When the capacitor gets fully charged it has polarity opposite to the voltage source, so net voltage is 0)

5)T = RC = 5 * 220 *10-6 = 1100 * 10-6 = 1.1 ms (ans)

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