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Two very large, nonconducting plastic sheets, each 10.0 cm thick, carry uniform

ID: 1319973 • Letter: T

Question

Two very large, nonconducting plastic sheets, each 10.0 cm thick, carry uniform charge densities ?1,?2,?3 and ?4 on their surfaces, as shown in the following figure(Figure 1) . These surface charge densities have the values ?1 = -5.30?C/m2 , ?2=5.00?C/m2, ?3 = 2.20?C/m2 , and ?4=4.00?C/m2. Use Gauss's law to find the magnitude and direction of the electric field at the following points, far from the edges of these sheets. a)What is the magnitude of the electric field at point A, 5.00 cm from the left face of the left-hand sheet? b)What is the magnitude of the electric field at point B, 1.25 cm from the inner surface of the right-hand sheet? c)What is the magnitude of the electric field at point C, in the middle of the right-hand sheet?

Explanation / Answer

formula to etermine Electric field due to Surface charge Density E = sigma/2eo


and in beweet the sheets it is given by E = sigma/2eo


so here PArtA :

E at 5cm at point A = sigma1/2e0

E1 = -5.3 e-6/(2*8.85e-12)

E1 = 2.99 *10^5 N/C

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sigma net in middle (at B )   = sigma2 + sigma 3

sigma = 5+2.2 = 7.2 e-6

so

EFat B = 7.2e-6/(8.85e-12)

EFat B = 8.13*10^5 N./C


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Electrif Field at C = sigma4/2eo

E = 4e -6/(2*8.85e-12)

E = 2.259*10^5 N/C