A proton is acted on by an uniform electric field of magnitude 233 N/C pointing

Question

A proton is acted on by an uniform electric field of magnitude 233 N/C pointing in the positive x direction. The particle is initially at rest.

(a) In what direction will the charge move?
---Select--- +x direction ?x direction +y direction ?y direction +z direction ?z direction

(b) Determine the work done by the electric field when the particle has moved through a distance of 2.45 cm from its initial position.
9.14e-19 J

(c) Determine the change in electric potential energy of the charged particle.
-1.98e-19 J

(d) Determine the speed of the charged particle.
m/s

Explanation / Answer

a) -Z direction

b) workdone = F*s = q*E*s = 1.6*10^-19*233*0.0245 = 9.14*10^-19 J

c) delta U = -workdone = -9.14*10^-19 J

d) 0.5*m*v^2 = KE

v = sqrt(2*KE/m) = sqrt(2*9.14*10^-19 J/1.67*10^-27) = 3.3*10^4 m/s

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