Question 7 of 8 Map co Sapling Learning The table below shows the data for purif

Question

Question 7 of 8 Map co Sapling Learning The table below shows the data for purification of a hypothetical protein. Complete the table by fillng in the missing values for the specific activity Step Total Protein Total Activity Specific Activity Yield Purification (mg) (units) 151000 135000 (units mg) 11.5 33.8 level (%) 100 89.5 Homogenization 13100 Salt fractionation 4.00 x 103 2.94 Number lon-exchange chromatography 118000 77.9 8.21 1250 Number Gel-filtration chromatography 48.3 78100 51.7 141 Number Affinity chromatography 1.35 51800 34.3 3340

Explanation / Answer

specific activity is obtained by dividing the total enzyme activity by total protein.

ion exchange chromatography: sp.activity= 118000 / 1250 = 94.4 units/mg

Gel filtration chromatography: sp.activity = 78100 / 48.3 = 1617units/mg

Affinity chromatography: sp.activity= 51800 / 1.35 = 38370units/mg

As the protein gets purified, the specific activity is having larger value since the impurities and other particles are removed.  

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