What is the magnitude of the resultant force? 002 (part 1 of 2) 10.0 points Thre

Question

What is the magnitude of the resultant force?

002 (part 1 of 2) 10.0 points Three charges are arranged in the (x, y) plane as shown y (m) -6 nC -9 nC -3 3 nC -5 -3-10 1 2 3 4 5 What is the magnitude of the resulting force on the -9 nC charge at the ori cO 8.98755 × 109 N . C2/m2 . Answer in units of N. 003 (part 2 of 2) 10.0 points What angle does the resultant force on the -9 × 10-9 C charge at the origin make with the positive x axis? Quadrant I lies between 0° and 90°, quadrant II between between 90°

Explanation / Answer

Here , for charge 6 nC ,

angle t1 = arctan(4/4) = 45 degree

electric force between two charges is given by

F = kq1 *q2 /d^2

F1 = 9*10^9*6*10^-9*9*10^-9 /(4^2 + 4^2)

F1 = 1.52 * 10^-8 N

Now , for charge 3 nC

angle , t2 = arctan(3/2) = 56.3 degree

and

F2 = 9*10^9*3*10^-9*9*10^-9/(2^2 + 3^2)

F2 = 1.87 * 10^-8 N

Now ,

for resultant

F = (-1.52*cos45 + 1.87*cos(56.3))*10^-8 i + j * (-1.52*cos45 - 1.87*sin(56.3))*10^-8

F = - 3.72 *10^-10 i - 2.11 *10^-8 j

magnitude is

F = 2.11 * 10^-8 N

magnitude of force F is 2.11 * 10^-8 N

Now,

angle , theta = 268.9 degree

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