File Edit View History Bookmarks Window Hoip HW 100: Ch. 19.7-19.10 Awen Carries

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File Edit View History Bookmarks Window Hoip HW 100: Ch. 19.7-19.10 Awen Carries Arm “ 7.45-. A Wire Carries An It Need Help? ResdinChat About N 1/2 points I Previous Answers SerCP9 19 P051 MLFB A wire carries an I, - 7.40-A current along the x-axis, and another wire cames an 12 5.40-A current along the y-axis, as shown in field at point P, located at x -4.00 m, y - 3.00 m? magnitude My Notes O Ask Your current along the y-axis, as shown in the figure below. What is the magnetic Use the expression for the magnetic field around a the two currents. current-carying wire to find the magnitude and direction of the magnetic field contribution from each of eld around a current-canrying wire to find the magnitude and direction of the magnetic feld contributon directionout of the page (4.00, 3.00) m Submit Answer Save Progress Pracice Another Version

Explanation / Answer

magnetic field due to a straight current carrying wire is B = uoi/2piR

so
i1 = 7.4 A

and y1 = 3 m

here B due to wire in x axis is Bx = (4*3.14e-7 * 7.4/(2*3.14 * 3)

Bx =   4.933 *10^-7 Tesla

Similarly By due to current on y axis By = 4*3.14e-7 * 5.4/(2*3.14* 4)

By = 2.7 *10^-7 Tesla

these two are now acting at right angles

so BNet^2 = Bx^2 +By^2

Bnet^2 = 4.93^2 + 2.7^2

Bnet = 5.62 *10^-7 Tesla -------->>>>>>>>>>>>>>>>answer

-------------------------

direction tan theta = Bx/By

tan theta = 4.933/2.7

tan theta = 1.8259

theta = 61.29 deg -out of apage ----<<<<<<<<<<<<<Answer

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