1) A magnetic B field with strength 1.8 T passes through a metal square loop mea

Question

1) A magnetic B field with strength 1.8 T passes through a metal square loop measuring 0.6 m on its side. If the B field is parallel to the loop's normal, then find the magnitude of the magnetic flux ? through the loop. (in units of Wb or Tm2)

2) If the loop is now rotated such that its normal is at an angle of 60 degrees with respect to the B field, then find the new magnetic flux ? through the loop.

3) If the loop rotates until its normal is perpendicular to the B field, then what is the magnetic flux ? through the loop?

Please explain.

Explanation / Answer

#1:

magnetic flux phi = NAB

where N is no .o f turns = 1

A is area = L^2

B is magnetic field

so

mag flux = 1 * 0.6*0.6 * 1.8

mag flux = 0.648 Tm^2 or Wb

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#2:

new flux = NAB cos thjeta

new flux =   0.649 * cos 60

flux = 0.324 Wb

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#3

when held Normal, theta = 90

so flux = NAB cos 90

flux = 0

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