Electrical Force Inside a Capacitor 2 cm apart 1.5 cm apart Data analysis: the a

Question

Electrical Force Inside a Capacitor

2 cm apart

1.5 cm apart

Data analysis:

the attractive electrical force equals the difference between the balance reading multipiled by g (9.81m/s/s)

- Plot the force (yaxis) versus voltage for each gap distance. Do a log-log plot also

-Plot the force (Y-axis) versus gap distance for each voltage. Do a log-log ploty also

Initial zero volt Voltage kV Scale Reading Final zero-volt 57.5g 1 57.3g 57.5 57.5g 2 57.2g 57.5 57.5g 3 57.0g 57.5 57.5g 4 57.0g 57.5 57.5g 5 56.6g 57.6 57.5g 6 56.5g 57.6

Explanation / Answer

in this question

force in capacitor equals to

=0.5*epsilon*e2

actually it does not depend on physical mass

case1

distance=2cm

E=V/d

calculate electricfield for each value of v

d=constant

example

E=1*103/2*10-2

AFTER THIS SUBSTITUTE IN ABOVE EQUATIONS GET THE VALUE OF FORCE

EXAMPLE 2 IS SIMILAR AS ABOVE

BUT TAKE DISTANCE=1.5CM

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.