Q1: A 0.34 kg rock is projected from the edge of the top of a building with an i
ID: 1317278 • Letter: Q
Question
Q1: A 0.34 kg rock is projected from the edge of the top of a building with an initial velocity of 9.03 m/s at an angle 37? above the horizontal.
The building is 14.4 m in height.
Assume: The ground is level and that the side of the building is vertical. The accelera- tion of gravity is 9.8 m/s2 .
At what horizontal distance, x, from the base of the building will the rock strike the ground?
Answer in units of m.
Q2: A golf ball is hit at ground level. The ball is observed to reach its maximum height above ground level 3.8 s after being hit. 0.97 s after reaching this maximum height, the ball is observed to barely clear a fence that is 674 ft from where it was hit.
The acceleration of gravity is 32 ft/s2 .
How high is the fence? Answer in units of ft.
Explanation / Answer
1)Using
s = ut +1/2 at^2
-14.4 = 9.03 t sin 37 - 1/2*9.8t^2
4.9t2 - 5.4343 t -14.4 = 0
t= 2.35626 sec
In this time the horizontal distance travelled is x = Ut cos(theat) = 9.03*2.35626* cos 37 = 16.992 m
2)
u = initial speed (ux, uy)
v = speed at time t
(Vx and Vy are horizontal and vertical components of V)
g= 32ft/s
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