Q: 1of 2 ) A bomber flies horizontally with a speed of 258 m/s relative to the g

Question

Q: 1of 2 ) A bomber flies horizontally with a speed of 258 m/s relative to the ground. The altitude of the bomber is 3750 m and the terrain is level. Neglect the effects of air resistance.

The acceleration of gravity is 9.8 m/s2 .

a) How far from the point vertically un- der the point of release does a bomb hit the ground?
Answer in units of m.

Q:2 of 2)

b) At what angle from the vertical at the point of release must the telescopic bomb sight be set so that the bomb hits the target seen in the sight at the time of release?

Answer in units of ?.

Explanation / Answer

a) Horizontal motion is independent of vertical motion ===> The bomb lands below the bomber ===>

d = 0.5 at^2
3750 m = 0.5 * 9.8 * t^2
t^2 =3750/4.9
t = 27.66 s

Bombs horizontal velocity = bomber horizontal velocity = 258 m/s

d =vt =258 * 27.66 = 7136.28 m (That is a)



tan^-1 = 7136.28/3750

angle = 62.27 degrees (That is b)

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