A proton is acted on by an uniform electric field of magnitude 353 N/C pointing

Question

A proton is acted on by an uniform electric field of magnitude 353 N/C pointing in the positive z direction. The particle is initially at rest.

(a) In what direction will the charge move?
---Select--- +x direction ?x direction +y direction ?y direction +z direction ?z direction

(b) Determine the work done by the electric field when the particle has moved through a distance of 3.95 cm from its initial position.
J

(c) Determine the change in electric potential energy of the charged particle.
J

(d) Determine the speed of the charged particle.
m/s

Explanation / Answer

a) positive z direction

b) W = qEd

q = 1.6 x 10-19C

E= 353 N/C

d = 3.95 cm

that gives

W = 2.231 x 10-18J

c) change in potential energy = -2.231 x 10-18J

d) 0.5mv2 =W

m= 6.7 x10-27kg

that gives speed v = 2.58x104m/s

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