An electron moving to the right at 7.5x10^5 m/s enters a uniform electric field

Question

An electron moving to the right at 7.5x10^5 m/s enters a uniform electric field parallel to its direction of motion. If the electron is to be brought to rest in the space of 4.0 cm. a. What direction is required for the electric field? b. What is the strength of electric field? An electron moving to the right at 7.5x10^5 m/s enters a uniform electric field parallel to its direction of motion. If the electron is to be brought to rest in the space of 4.0 cm. a. What direction is required for the electric field? b. What is the strength of electric field? a. What direction is required for the electric field? b. What is the strength of electric field?

Explanation / Answer

A) the electron always moves in the opposite direction of the electric field...hence the direction of the required electric field is in the direction of its motion

B) W = 0.5*m*v^2..
but W = F*S = q*E*S...
then q*E*S = 0.5*m*v^2....

E = 0.5*9.1*10^-31*(7.5*10^5)^2 / (1.6*10^-19*0.04) = 40 N/C or V/m

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