Use the steps outlined above to find the magnitude of the acceleration a of a ch

Question

Use the steps outlined above to find the magnitude of the acceleration a of a chair and the magnitude of the normal force FN acting on the chair: Yusef pushes a chair of mass m = 45.0kgacross a carpeted floor with a force F? p (the subscript 'p' here is lowercase and throughout the question) of magnitude Fp = 170N directed at ? = 35.0degrees below the horizontal (Figure 1) . The magnitude of the kinetic frictional force between the carpet and the chair is Fk = 91.5N .

What is the magnitude of the acceleration a of the chair? What is the magnitude of the normal force FN acting on the chair?

Explanation / Answer

horizontal component of the force applied= 170 cos 35

=139.255 N

so acceleration = (139.255-91.5)/45

=1.06 m/s^2

magnitude of normal force= 170 sin(35) + mg

=0.573*170 + 9.81*45

=538.86 N

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