Use the solubility table to answer the following you do not need to mix any chem

Question

Use the solubility table to answer the following you do not need to mix any chemicals. Circle all of the following compounds that will not dissolve completely (or form a ppt) in HCI(aq) AI(OH)_3(s) CUCO_3(S) Pb(NO_3)_2(aq) CaSO_4(s) BaCl_2(aq) AgNO_2(aq) Circle all of the following solutions that will not precipitate with addition of CuSO_4 NaOH(aq) BaCl_2(aq) Pb(NO_3)_2(aq) K_2CO_3(aq) CuCl_2(aq) NH_4Cl(aq) Circle all of the following compounds that will not precipitate with addition of Mg(IO_3)_2aq) CaCl_2(aq) NH_4OH(aq) ZnSO_4(aq) Ba(NO_3)_2(aq) Pb(NO_3)_2(aq) K_2CO_3(aq)

Explanation / Answer

1) HCl(aq) ---->H+(aq) + Cl-(aq)

BaCl2(s)<--->Ba2+(aq)+Cl-(aq)

HCl has Cl- ions in the solutions so any compound with Cl- ions in solution will be thrown out of the solution due to excess of common ion,Cl- .(common ion effect due to excess of product ion,reverse rxn is accelerated- Le Chatlier's principle) ,so BaCl2 is precipitated.

2)CuSO4--->Cu2+ +SO42-

common ion Cu2+ with CuCl2 will cause the precipitation of the same(excess of product ion,reverse reaction favored)

Rest all will not precipitate out but dissolve

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