A 3.900 kg block of wood rests on a steel desk. The coefficient of static fricti

Question

A 3.900 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is s = 0.605 and the coefficient of kinetic friction is k = 0.305. At time t = 0, a force F = 14.2 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times: t=0, t>0.

Consider the same situation, but this time the external force F is 28.7 N. Again state the force of friction acting on the block at the following times: t=0, t>0.

Explanation / Answer

a)force required to move=0.605*3.9**9.81

=23.14

so f= 14.2 : t=0

= 14.2 : t>0

b) f= 23.14 : t=0

f=0.305*9.81*3.9

=11.66 N : t>0

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