Using this stimulation: http://phet.colorado.edu/en/simulation/forces-and-motion

Question

Using this stimulation:

http://phet.colorado.edu/en/simulation/forces-and-motion

Choose the force graph mode, wood, the small crate as an object (m=100kg). Set the initial position = - 8.0 m then enable the force, acceleration, velocity and position graphs. a. What is the magnitude of maximum static friction force? coefficent of static force=0.5

c. What are the corresponding values of friction force and net force? Write your results in the following table: Applied force [N] 100, 150, 200, 250, 300, 350, 400, 450, 500

Find Corrosponding :

friction force [N] and Net horizontal force for each applied force value

d. What did happen when the magnitude of the applied force is greater than that of the maximum static friction force? Did you notice the change in friction force?

Explanation / Answer

a. What is the magnitude of maximum static friction force?

Ans: Max static force = 0.5*100*9.8 N = 490 N

c.

Applied force [N] 100, 150, 200, 250, 300, 350, 400, 450, 500

friction force [N] 100, 150, 200, 250, 300, 350, 400, 450, 490

Net horizontal force [N] 0, 0, 0, 0, 0, 0, 0, 0, 10

When the magnitude of applied force is greater than that of maximum static friction force, the friction force is no longer able to sustain the motion of the crate and it starts moving, This acceleration is due to the differnce which exceeded maximum friction force = 500-490N = 10 N and the body starts moving as a result of the net horizontal force.

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