On all of these but number 1 I don\'t know what I am doing wrong! Can you show c

Question

On all of these but number 1 I don't know what I am doing wrong! Can you show calculations please! It may just be a simple conversion error. Thanks!

1.) (a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is6.00 cm2? 15.9 nC

(b) Find the maximum charge if nylon is used between the plates instead of air.

2.) Two protons are released from rest, one from location 1 and another from location 2. When these two protons reach location 3, the first proton has a speed that is 2 times the speed of the second proton. If the electric potentials at locations 1 and 2 are 231 V and 115 V, respectively, what is the electric potential at location 3?

4.) Two parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts.

(a) What is the electric field strength between them, if the potential 7.45 cm from the zero volt plate (and 2.55 cmfrom the other) is 633 V?

answer in kV/m

(b) What is the voltage between the plates?

Explanation / Answer

1.)a.)The dielectric strength of air is not a fixed number. An accepted value is 3*10^6 V/m, The field in the capacitor is ?/? where ? = Q/A. For air ? = ?0 = 8.85*10^-12 F/m The maximum charge is then

Q= 1*3*10^6*0*0.0006*8.85*10^-12 = 1.593*10^-8 C = 15.93 nC

b.)The dielectric strength of nylon is 25*10^6; the dielectric constant is 3.5, so ? = 30.975*10^-12 F/m

Q = 25*10^6*0*0.0006*30.975*10^-12 = 4.64625 x 10^-7 C = 464.625 nC

2.)Assuming these protons are released independently, that is, the 2 protons do not affect each other's motion is any way,
q(V1) = q(V3) + (1/2)(m)(2v)

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