The photoelectric threshold wavelength of a tungsten surface is 272nm . Part A W

Question

The photoelectric threshold wavelength of a tungsten surface is 272nm .

Part A

What is the threshold frequency of this tungsten?

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Part B

What is the work function (in eV) of this tungsten?

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Part C

Calculate the maximum kinetic energy (in eV) of the electrons ejected from this tungsten surface by ultraviolet radiation of frequency 1.47

The photoelectric threshold wavelength of a tungsten surface is 272nm .

Part A

What is the threshold frequency of this tungsten?

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Part B

What is the work function (in eV) of this tungsten?

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Part C

Calculate the maximum kinetic energy (in eV) of the electrons ejected from this tungsten surface by ultraviolet radiation of frequency 1.47

Explanation / Answer

v= flamda

= 3*10^8 = 272*10^-9 * frequency

= 1.1*10^15 HZ = frequency

2]work function = h[thresold frequency ]

= 7.30*10^-19 J

= 4.56 eV

3]energy = KEmax + work function

= 6.08 eV - 4.56 eV = KE max = 1.52 eV

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