1. An object is placed 70.0 cm from a screen. (a) Where should a converging lens

Question

1. An object is placed 70.0 cm from a screen.

(a) Where should a converging lens of focal length 6.5 cm be placed to form an image on the screen?

(b) Find the magnification of the lens.

2. A flint glass plate (n = 1.66) rests on the bottom of an aquarium tank. The plate is 8.00 cm thick (vertical dimension) and covered with water (n = 1.33) to a depth of 12.0 cm. Calculate the apparent thickness of the plate as viewed from above the water. (Assume nearly normal incidence of light rays.)

A goldfish is swimming inside a spherical bowl of water having an index of refraction n = 1.333. Suppose the goldfish is p = 10.4 cm from the wall of a bowl of radius |R| = 17.8 cm, as in the figure below. Neglecting the refraction of light caused by the wall of the bowl, determine the apparent distance of the goldfish from the wall according to an observer outside the bowl.
cm behind the glass

Explanation / Answer

a) p + q = 70
so p = 70-q

1/(70-q) + 1/q = 1/6.5

q=7.25 or 62.75 cm

b) M = -q/p = -7.25/62.75=-0.116

M = -62.75/7.25=-8.66

3.

Using snells law:

n1/do + n2/di = (n2-n1)/R

1.33/10.4+1/di = (1.333-1)/17.8

di = - 9.16 cm

the apparent distance of the goldfish from the wall = 9.16 cm

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