A 0.20 mol sample of an ideal gas goes through the Carnot cycle of figure below.

Question

A 0.20 mol sample of an ideal gas goes through the Carnot cycle of figure below. (Figure 1)

Figure 1 of 1

Part A

Calculate the heat Qh absorbed.

Express your answer using four significant figures.

Part B

Calculate the heat Qc rejected.

Express your answer using four significant figures.

Part C

Calculate the work done.

Express your answer using four significant figures.

Part D

Use these quantities to determine the efficiency.

Part E

Find the maximum temperature.

Express your answer using four significant figures.

Part F

Find the minimum temperature.

Express your answer using four significant figures.

Physics

Explanation / Answer

Tmax = PV/nR = 4*2/(0.2*0.0821) = 487.21 K

Tmin = PV/nR = 2.050*3.224/(0.2*0.0821) = 402.51 K

Qh = nRTmax ln(2/1) = 0.2*0.0821*487.21*ln2 = 5.545 J

Qc = nRTmin ln(1.612/3.224) = 0.2*0.0821*402.51*ln(0.5) = -4.581 J

Work Done in a cycle; W = Qh + Qc = 5.545 - 4.581 = 0.964 J

e = W/Qh = 0.964/5.545 = 0.1738.

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