A 0.17 kg hockey puck slides across the ice at 3.4 m/s. A hockey player then use
ID: 1632737 • Letter: A
Question
A 0.17 kg hockey puck slides across the ice at 3.4 m/s. A hockey player then uses her stick to exert a constant 0.13 N force on the puck opposite the direction of its velocity over a distance of 2.0 m. What is the puck's speed after coming in contact with her stick?
A. 3.4 m/s
B. 3.8 m/s
C. 3.1 m/s
D. 2.9 m/s
Which best describes the frequency of an oscillator undergoing simple harmonic motion?
A. the time for one full oscillator cycle of motion
B. the oscillator's number of cycles per second
C. the maximum distance from equilibrium
D. the kinetic energy of the oscillator
Explanation / Answer
1. Lets assume that hockey pluck is moving in positive x direction
initial velocity(u) = 3.4m/s
accelaration (a)= force/ mass = 0.13/0.17 = 0.765
distance (s)= 2m
we know,
V2=u2 -2*a*s = 3.42 -2*0.765 *2 =8.5
V=sqrt (8.5 ) =2.91 m/s
2. The frequency (f) of an oscillation is measure in hertz (Hz) it is the number of oscillations per second
so. Option B is the correct option
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