1) A double-slit system is used to measure the wavelength of light. THe system h

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Question

1) A double-slit system is used to measure the wavelength of light. THe system has slit spacing d=18 um and slit-to-screen distance L=2.4m

If the m=1 maximum in the interference pattern occurs 7.1 cm from screen center, what is the wavelength?

2) A double-slit experiment with d=2.5x10^-2 mm and L=80cm uses lambda=550nm light.

Find the spacing between adjacent bright fringes.

3) In bright light, the human eye's pupil diameter is about 2 mm.

If diffraction were the limiting factor, what's the eye's minimum angular resolution under these conditions, assuming 570-nm light?

1) A double-slit system is used to measure the wavelength of light. The system has slit spacing d=18 um and slit-to-screen distance L=2.4m

If the m=1 maximum in the interference pattern occurs 7.1 cm from screen center, what is the wavelength?

d (y/L) = m lambda

==> lambda = d y/(m L) = 18e-6*7.1e-2/(1*2.4) = 533 x 10^-9 m = 533 nm

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2) A double-slit experiment with d=2.5x10^-2 mm and L=80cm uses lambda=550nm light.

Find the spacing between adjacent bright fringes.

d (y/L) = m lambda

==> y = L m lambda/d = 0.80 * 1 * 550e-9/2.5e-2 = 1.76 x 10^-5 m

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3) In bright light, the human eye's pupil diameter is about 2 mm.

If diffraction were the limiting factor, what's the eye's minimum angular resolution under these conditions, assuming 570-nm light?

Theta = 1.22 lambda/D = 1.22 * 570e-9/(2e-3) = 0.0003477 radians = 0.0199 degrees

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