tried to follow two similar problems on chegg and got two incorrect answers have
ID: 1303592 • Letter: T
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tried to follow two similar problems on chegg and got two incorrect answers have only one more submission before it locks help would be much appreciated thanks
A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.330 m2. At the window, the electric field of the wave has rms value 0.0235 V/m. How much energy does this wave carry through the window during a 26.0-s commercial? A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.330 m2. At the window, the electric field of the wave has rms value 0.0235 V/m. How much energy does this wave carry through the window during a 26.0-s commercial? A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.330 m2. At the window, the electric field of the wave has rms value 0.0235 V/m. How much energy does this wave carry through the window during a 26.0-s commercial? A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area 0.330 m2. At the window, the electric field of the wave has rms value 0.0235 V/m. How much energy does this wave carry through the window during a 26.0-s commercial?Explanation / Answer
E_max = (sqrt(2)) (E_rms) = (sqrt(2)) * (0.0235) = 0.033234 V/m
S = (E_max)^2/(2 u0 c) = (0.033234^2)/(2*(4*3.1416e-7)*(3e8)) = 1.46488e-6 V/m
E = S A t = 1.46488e-6 * 0.330 * 26 = 12.6 uJ
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