Uranium-235 has 92 protons and 143 neutrons. When 235 U captures a very slow neu

Question

Uranium-235 has 92 protons and 143 neutrons. When 235U captures a very slow neutron, it becomes 236U, and promptly breaks up by fission, usually into two smaller nuclei and 2 neutrons, plus a lot of energy. Assume that the two smaller nuclei plus the 2 neutrons have a rest mass of 235.8385 u. What fraction of the initial mass is converted into energy? DATA: mass of 235U = 235.0439 amu; mass of a neutron =1.0087 amu.

9.0710-4

Assume that the result of the previous problem is an average for 235U fission. Calculate the total mass of 235U which must undergo fission to produce the same amount of energy as one million kilograms of chemicals in a combustion reaction for which the fraction of the mass becoming energy is 0.810

I cant solve the second part....

Explanation / Answer

9.07 x 10^(-4) *M = 10^(6) * (0.8 x 10) ==> M=8/9.07 x 10^(10) = 8.82 x 10^(10) Kg.

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