Light with wavelengths from 400 nm to 700 nm is Involved in a two slit interfere

Question

Light with wavelengths from 400 nm to 700 nm is Involved in a two slit interference experiment with a slit spacing of 0.0045 mm At what angle will the second order maximum be located for blue light (400 nm)? 10degrees 20 degrees 30 degrees 40degrees 50degrees How many full order spectra (from 400nm to 700nm) can be seen above the central bright fringe? 2 4 6 8 10 How would the previous answer change if the slit spacing ~doubled'? increase Decrease Remain the same It depends on the distance me screen is from the slits. No spectra would appear.

Explanation / Answer

Number 1)

Apply sin(angle) = m(wavelength)/d

sin(angle) = (2)(400 X 10-9)/(4.5 X 10-6)

angle = 10.2o (Round to 10o)

Number 2)

Apply 1 = m(wavelength)/d

1 = m(700 X 10-9)/(4.5 X 10-6)

m = 6.42 but since you cant have a partial portion of a full order, you must round down.

Thus m = 6

Number 3)

From the formula, you can see that slit spacing and m are directly proportional. Thus if spacing is doubled, m value doubles. Doubles means it increases.

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