A homeowner is trying to move a stubborn rock from his yard which has a mass of

Question

A homeowner is trying to move a stubborn rock from his yard which has a mass of 425 kg. By using a lever arm (a piece of metal rod) and a fulcrum (or pivot point) the homeowner will have a better chance of moving the rock. The homeowner places the fulcrum d = 0.222 m from the rock so that one end of the rod fits under the rock?s center of weight. The homeowner can apply a maximum force of 623 N at the other end of the rod, what is the minimum total length L. of the rod required to move the rock? Assume that the rod s massless and nearly horizontal so that the weight of the rock and homeowner?s force are both essentially vertical.

Explanation / Answer

m = mass of the rock = 425 kg
g = acceleration due to gravity = 9.81 m/s

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