A bubble of 6.00 mol (monatomic) helium is submerged at a certain depth in liq-

Question

A bubble of 6.00 mol (monatomic) helium is submerged at a certain depth in liq- uid water when the water ( and thus the helium ) undergoes a temperature increase T of 200C at constant pressure. As a result, the bubble expands.
(a) How much heat Q is added to the helium during the expansion and temperature increase? (b) What is the change Eint in the internal energy of the helium during the temperature increase?

(c) How much work W is done by the helium as it expands against the pressure of the surrounding water during the temperature increase?

Explanation / Answer

As the process is isobaric process,work done will be P?V. where ?V is increase in volume of helium bubble.according to laws of thermodynamics-

Q = P?V + ?U

As internal energy change is related to temp change as-

?U = 3/2 *nR*?T

       =3/2*6*8.314*200

       = 14695.2 jule

and P?V =n*R*?T

W =6*8.314*200

W =9976.8 jule

Q =9976.8 + 14695.2

Q=24672 jule

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