You are asked to construct a mobile with four equal m = 125 kg masses, and three

Question

You are asked to construct a mobile with four equal m = 125 kg masses, and three light rods of negligible mass and equal lengths. The rods are of length 75 cm.

http://www.webassign.net/ncsuplsemech2/6-post-002.gif

(a) At what location on the level 1 rod should the free end of rod 2 be attached? L1 =

(b) At what location on the level 2 rod should the free end of rod 3 be attached? L2 =

(c) At what location on the level 3 rod should the whole assembly be suspended from so that the mobile is in equilibrium? L3 =

Explanation / Answer

a) 75/2 = 37.5
b) 75/3 = 25
c) 75/4 = 18.75
It makes since since the first rod is half the distance, second a third of the distance, and the third rod a fourth of the distance.

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