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LON-CAPA Cover Pa x fR Mail Inbox: [LON-C x D Busta Rhymes-Tou x C question I Chegg.c x LON-CAPA Course Cox C Homework Help Se x C question I Chegg.c x Closed-End Air Col x LON-CAPA p 07 https: c/53/7f4b174ae6f 55 4ffe44ee27cbc9908b2 b5222 32 fd21b5a36b63b88, 1b847983 (d97a6242bf4d620b3c51a2 d37ab0fdf32 d82 23f7c6765ab3763a0 18769964 c2f88eldf 57073da 1#04. Messages Courses Help Logout Joseph Raymond Zajac v Stud section: 730) PHY 233B Fall 2014. Main Menu l contents Grades Due in: 0 d 00:05:34 submit Early Timer Notes d Evaluate Feedback Print Course Contents Practice Exam #3 (Online between 11/22 Sa 11 AM and 11/23 Su 11 PM) p 07 An object is performing simple harmonic motion. The maximum value of the object's speed is 1.49 m/s and the maximum value of its acceleration is 7.01 m/s2 Determine the amplitude of the motion (in m) A: 4.94x10-2 B: 7.16x10-2 C: 1.04x10-1| D: 1.51x 10-1 E 2.18x10-1 F: 3.17x10-1 SG: 4.59x 10-1 H: 6.66x10-1 Submit Answer Tries 0/12 Determine the angular freguency of the motion (in 1/s) A: 6.39x10-1 B: 8.50x10-1 C: 1.13 OD: 1.50l E: 2.000 O F: 2.66 O G: 3.54 H: 4.70 Sub Answer Answer Submitted: Your final submission will be graded when the time limit is reached Tries 1/12 Previous Tries Post Discussion Send Feedback 4:25 PM 23/2014

Explanation / Answer

V_max=1.49 m/sec
a_max=7.01 m/sec^2

we use the formul,
V_max=A*w
a_max=A*w^2
now,
V_max=A*w
a_max/V_max=(A*W^2)/A*w
==>
w=a_max/V_max
w=7.01/1.49
w=4.704 rad/sec

A)

amlitude A=v_max/w
A=1.49/4.704
=0.3167 m
=3.167*10^-1 m

B)
w=4.704 rad/sec

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