LON-CAPA Course Ce x LON-CAPA water lev x CAPA Floating x C Homework Help Ask x
ID: 1291339 • Letter: L
Question
LON-CAPA Course Ce x LON-CAPA water lev x CAPA Floating x C Homework Help Ask x C Homework Help Sea x C Please Dont Just Gue X Mail Inbox (4890 x 2 LON-CAPA Water str x C e https: lite msu.edu 4db2a40e 75 13 31 f57 2953 14bec27edfb1de251 5230527 dfb4 be 5240080 Messages Courses Help Logout Joseph Raymond Zajac v Student section: 730) PHY 233B Fall 2014. Main Menu contents Grades Timer Notes Evaluate Feedback Print HW #9 (11/13 Th 11:59 PM Water stream Course Contents The figure shows a water tank with a valve at the bottom Valve If this valve is opened, what is the maximum height attained by the water stream coming out of the right side of the tank with respect to the baseline where the height h is mesured from? Assume that h 14.7 m, LE 2.48 m, and e 26.1 and that the cross-sectional area at A is very large compared with that at B 2.69 m Sub Answer Incorrect. Tries 8/12 Previous Tries Threaded View Chronological View Other Views My general references on what is marked as NEW Export Mark NEW posts no longer neW NEW Hmm Rachel D King Reply (Mon Nov 10 09:34:59 pm 2014 (EST)) So I found the velocity by v sqrt[2g(h-Lsin(theta))], then found y max I(vsin(theta)) 2l/(2g). Not sure what I did wrong NEW Re: Hmm Lindsey Renee Kemmerling Reply (Tue Nov 11 11:02:43 am 2014 (EST)) For the final H you then have to add Lsin(theta) to the height you have NEW Re: Re: Hmm Rachel D King Reply (Tue Nov 11 12:41:50 pm 2014 (EST)) Thank you My Settings for this discussion: 1. Display All posts 2. Not new Once marked not NEW Change Threaded View Chronological View Other Views My general references on what is marked as NEW METK NEW DOSES no longer new :45 PM 2014Explanation / Answer
h = 14.7 m, L = 2.48 m, theta = 26.1
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.