A positively charged particle of mass 6.90 A positively charged particle of mass

Question

A positively charged particle of mass 6.90

A positively charged particle of mass 6.90 A? 10-8 kg is traveling due east with a speed of 69.3 m/s and enters a 0.307-T uniform magnetic field. The particle moves through one-quarter of a circle in a time of 4.71 A? 10-3 s, at which time it leaves the field heading due south. All during the motion the particle moves perpendicular to the magnetic field. (a) What is the magnitude of the magnetic force acting on the particle? (b) Determine the magnitude of its charge.

Explanation / Answer

While the particle is in the field it travels distance d = 45*4.2E-3 = 0.189000 m
radius r = 2d/pi = 0.120321 m.
A. F = mv^2/r = 0.121176 N
B. omega = v/r = 374.000 rad/s
q = m*omega/B = 6.26232E-5 C

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