An object 5.0 cm tall is 30cm from a concave lens. The resulting virtual image i

Question

An object 5.0 cm tall is 30cm from a concave lens. The resulting virtual image is one-fifth as large as the object.

Part A

What is the focal length of the lens?

Express your answer using two significant figures.

Part B

What is the image distance?

Express your answer using two significant figures.

_____

An object 5.0 cm tall is 30cm from a concave lens. The resulting virtual image is one-fifth as large as the object.

Part A

What is the focal length of the lens?

Express your answer using two significant figures.

f = ____ cm  

Part B

What is the image distance?

Express your answer using two significant figures.

di =

_____

  cm

Explanation / Answer

apply magnification m = -v/u = -1/5

u = - 5 v

so

f = uv/u+v     - 5v * v/( 4v)

f = 4v/5

f = 4 * 30/5*5

f = 4.8 cm

--------------------------

v = 30/5 = 6 cm

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