One end of a light hacksaw blade is clamped in a vise with the long axis of the

Question

One end of a light hacksaw blade is clamped in a vise with the long axis of the blade horizontal and with the sides vertical. A 0.745- kg mass is attached to the free end. When a steady sideways force of 30.5 N is applied to the mass it moves aside 12.8 cm from its equilibrium position. When released, the blade moves back and forth with harmonic motion. Approximately how many complete oscillations will the blade make in 20.0 s when the force is removed?

Please show all work and explain your methods.

Explanation / Answer

Assuming k = 30.5N / 0.128m = 238.281 N/m

For shm .. ?

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