As described in the manual, consider a 10 cc syringe is connected to a 50 cc syr

Question

As described in the manual, consider a 10 cc syringe is connected to a 50 cc syringe. Information of the syringes are as follows:
(mass of 10 cc piston) = 16 g
(mass of 50 cc piston) = 60.6 g
(diameter of 10 cc piston) = 14.7 mm
(diameter of 50 cc piston) = 28.0 mm.

(a) What is the pressure exerted by the 10 cc piston onto the air underneath?

(b) If a 50 g mass is placed on the 10 cc piston, what is the pressure exerted by the 10 cc piston onto the air underneath?

(c) If a force probe is attached to the 50 cc piston, what do you expect will be the force measurement while a 50 g mass is placed on the 10 cc piston? Answer in N.

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I already found the answers to a and b, they are 0.9248 kPa and 3.8149 kPa. However, I cannot figure out Part c. Please help.

Explanation / Answer

P'=P2

F'/A=(3.8149*103)

F'=(pi*(28*10-3)2/4)*(3.8149*103)

F'=2.35 N

Force acting on the air by 50 cc piston is

F=mg=(60.6*10-3)*9.8=0.594 N

So force measure

dF=2.35-0.594=1.756 N

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