A 55.0-kg woman stands at the rim of a horizontal turntable having a moment of i

Question

A 55.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia of 440 kg · m2 and a radius of 2.00 m. The turntable is initially at rest and is free to rotate about a frictionless vertical axle through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.50 m/s relative to the Earth. (a) In what direction does the turntable rotate? clockwise counterclockwise Correct: Your answer is correct. With what angular speed does the turntable rotate? rad/s (b) How much work does the woman do to set herself and the turntable into motion? J

Explanation / Answer

L1 + L2 = 0

-mvR + I*w = 0

W = mvR/I = (55*1.5*2)/(440) = + 0.375 rad/s in couter clockwise

KE = 0.5*mv^2 + 0.5*I*w^2

KE = (0.5*55*1.5*1.5)+(0.5*440*0.375*0.375) = 92.8125 J

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