A puck slides on a surface for 5.6 m before it stops. If it was moving at a velo

Question

A puck slides on a surface for 5.6 m before it stops. If it was moving at a velocity of 15 m/s and has a mass of 1.2 kg, what is the force of friction exerted on the puck? There is a non-conservative work done on the puck equal to the change in kinetic energy.

W_{NC} = rac{1}{2}mv_{1}^{2} + mgy_{1} = rac{1}{2}mv_{2}^{2} + mgy_{2} + F_{fr}d

A puck slides on a surface for 5.6 m before it stops. If it was moving at a velocity of 15 m/s and has a mass of 1.2 kg, what is the force of friction exerted on the puck? There is a non-conservative work done on the puck equal to the change in kinetic energy. Solve using energy conservation with dissipative forces method. WNC = W_{NC} = rac{1}{2}mv_{1}^{2} + mgy_{1} = rac{1}{2}mv_{2}^{2} + mgy_{2} + F_{fr}d

Explanation / Answer

Ei + W friction = Ef

Ei = 1/2 mv^2

W friction = - F d

Ef = 0

1/2 mv^2 - F d = 0

0.5*1.2*15^2 - F*5.6 = 0

F=24.1 N

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