A puck of mass 0.20 kg approaches a second, identical puck that is stationary on

Question

A puck of mass 0.20 kg approaches a second, identical puck that is stationary on frictionless ice. The initial speed of the moving puck is 6.0 m/s. After the collision, one puck leaves with a speed v1 at 30° to the original line of motion. The second puck leaves with speed v2 at 60°. Calculate v1 and v2.

Explanation / Answer

Using conservation of momentum along the line of motion: m*v = m*v1cos(30) + m*v2cos(60) => 6.0 = v1*cos(30) + v2*cos(60) .... eqn 1 Using conservation of momentum perpendicular to line of motion: m*v1sin(30) = m*v2sin(60) => v1*sin(30) = v2*sin(60) 6.0 = x*cos(30) + y*cos(60) x*sin(30) = y*sin(60) any solver can solve this. x~5.19615, y~3

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