A merry-go-round is stationary. A dog is running on the ground just outside its

Question

A merry-go-round is stationary. A dog is running on the ground just outside its circumference, moving with a constant angular speed of 0.710 rad/s. The dog does not change his pace when he sees what he has been looking for: a bone resting on the merry-go-round one third of a revolution in front of him. At the instant the dog sees the bone (t = 0), the merry-go-round begins to move in the direction the dog is running, with a constant angular acceleration of 0.0165 rad/s2.

(a) At what time will the dog reach the bone? (in seconds)

(b) The confused dog keeps running and passes the bone. How long after the merry-go-round starts to turn do the dog and the bone draw even with each other for the second time? (in seconds)

Explanation / Answer

We are not both wrong.

In the below equations let d??, v=?, a=d?/dt

d = d? + v?t +

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