1. A conducting rod is moving through a magnetic field, as in the drawing. The m

Question

1. A conducting rod is moving through a magnetic field, as in the drawing. The magnetic field strength is 0.65 T, and the speed of the rod is 5.8 rn/s. Suddenly, the field strength decreases to 0.48 T. To what value must the speed y of the rod be adjusted to reestablish the cml induced between the ends of the rod at its Initial value? 2. Inductor 1 stores the same amount of energy as inductor 2, although Its Inductance Is only half the inductance of Inductor 2. What is the ratio I1/I2 of the currents In the two inductors? A step-down transformer has a turns ratio of 1:10, and its primary is connected across the terminals of a standard 120-V wall socket. A 330-Omega resistor is connected across the secondary of What power P is dissipated in the resistor?

Explanation / Answer

1) emf = B L V

so to keep same emf

B1 v1 = B2 v2

0.65*5.8 = 0.48*v

v=0.65*5.8/0.48= 7.85 m/s

2)

E = 1/2 L I^2

so to have same energy

L1 I1^2 = L2 I2^2

L2/2 I1^2 = L2 I2^2

I1^2/I2^2 = 2

I1/I2 = sqrt(2) = 1.414

3)

V1/V2 = N1/N2

so V2 = 12 V

P = V^2/R = 12^2/330= 0.436 W

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