1. An astronaut is out in space far from any large bodies. She uses her jets to
ID: 1286310 • Letter: 1
Question
1. An astronaut is out in space far from any large bodies. She uses her jets to start spinning, then releases a baseball she has been holding in her hand. How would you describe the path of the baseball after it leaves the astronaut's hand? a) It continues to circle the astronaut with the same radius it had before leaving the astronaut's hand. b) It circles the astronaut, spiraling closer. c) It moves of in an ever -widening circular arc. d) It stops moving the instant the astronaut let's go. e) It moves off in a straight line tangential to the point of release. 2.A wheel spins with a constant angular velocity (omega). Two points, A and B, are marked on the wheel as shown in the diagram. Which of the following statements are true? a) Point B has a higher angular velocity than point A. b) Point A has a negative angular velocity, while point B has a positive angular velocity. C) Point B will rotate through a larger angle (theta) than point A in the same amount of time. d) Both points have the same tangential speed. e) Point A has a higher tangential speed than point B. f) Point B has a higher tangential speed than point A. 3. A ball of mass in is tied to the end of string of length L. The ball is swung in a circle with an angular velocity omega. How does the tension in the string FT change if the length of the string is halved (1/2 L) while maintaining the same angular velocity? a) The tension would remain constant (FT). b) The tension would increase by a factor of 2 (2 F T). c) The tension would increase by a factor of 4 (4 FT ). d) The tension would decrease by a factor of 2 (1/2 F T). e) The tension would decrease by a factor of 4(1/4 F T). f) The tension would increase by a factor of 3 (3 FT).Explanation / Answer
1. e) it moves off in a straingh line tangential to the point of release.
2. angular velocity will be same for all points. so angle moved ( angle = w *t)
v = w*r
which has large distance from centre will more tang. velocity.
so point (f)
as B is far so B has hgher speed than A.
3) T = mv^2 / L =Ft
now L = L/2
T' = mv^2 / (L/2) = 2mv^2 / L = 2Ft
option B) would increase by factor of 2.
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