?1. Each of 140 id entical blocks sitting on a frictionless surface is connected

Question

?1. Each of 140 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 140 N.

A. What is the tension in the string connecting block 140 to block 139?

B.What is the tension in the string connecting block 70 to block 71?

2. The three ropes in the figure are tied to a small, very light ring. Two of the ropes are anchored to walls at right angles, and the third rope pulls as shown. What are T1and T2, the magnitudes of the tension forces in the first two ropes?

A. T1=

B T2=

3. The two angled ropes used to support the crate in the figure below can withstand a maximum tension of 1700N before they break.

A. What is the largest mass the ropes can support?

4. The forces in the figure are acting on a 3.3kg object.

A. Find the value of ax, the x-component of the object's acceleration.

B. Find the value of ay, the y-component of the object's acceleration.

?1. Each of 140 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 140 N. A. What is the tension in the string connecting block 140 to block 139? B.What is the tension in the string connecting block 70 to block 71? 2. The three ropes in the figure are tied to a small, very light ring. Two of the ropes are anchored to walls at right angles, and the third rope pulls as shown. What are T1and T2, the magnitudes of the tension forces in the first two ropes? A. Find the value of ax, the x-component of the object's acceleration. B. Find the value of ay, the y-component of the object's acceleration. A. What is the largest mass the ropes can support? 4. The forces in the figure are acting on a 3.3kg object. A. T1= B T2= 3. The two angled ropes used to support the crate in the figure below can withstand a maximum tension of 1700N before they break.

Explanation / Answer

frictionless surface

the tension between block n and (n+1) is T(n)

from the 2nd Law of Newton

acceleration a=F/140m =T(n)/(140m -n*m) ; a is the samefor all blocks

=> T(n)=F*(140-n)/140 ; F=140 N

n=139 => T(139)=1N

(2)  the tension in the string connecting block70to block71

n=70 => T(70)=70N

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