consider the system of massless pulley and masses shown in the diagram . If the

Question

consider the system of massless pulley and masses shown in the diagram . If the coefficient of static and kinetic friction on mass 1 ( 2.00 kg ) is 0.600 and 0.140 respectively ,

a- What is the maximum value of mass 2 that would allow the system to stay in equilibrium ?

b- If mass 2 is 5.00 kg , Find the acceleration of each of the masses ?

consider the system of massless pulley and masses shown in the diagram . If the coefficient of static and kinetic friction on mass 1 ( 2.00 kg ) is 0.600 and 0.140 respectively , a- What is the maximum value of mass 2 that would allow the system to stay in equilibrium ? b- If mass 2 is 5.00 kg , Find the acceleration of each of the masses ?

Explanation / Answer

a) sum forces

m g - friction = (m + M) a

since not moving a = 0

m g - u M g = 0

m = u M = 0.6*2 = 1.2 kg

b)

now nonzero

so mg - u M g = (m + M)a

5*9.81 - 0.14*2*9.81=(2+5)*a

a=6.6 m/s^2

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