A force of magnitude 4.90 units acts on an object at the origin in a direction ?

Question

A force

of magnitude 4.90 units acts on an object at the origin in a direction ? = 44.0 above the positive x-axis. (See the figure below.) A second force

of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force

magnitude     units direction     counterclockwise from the +x-axis A force F right arrow 1 of magnitude 4.90 units acts on an object at the origin in a direction ? = 44.0 above the positive x-axis. (See the figure below.) A second force F right arrow 2 of magnitude 5.00 units acts on the object in the direction of the positive y-axis. Find graphically the magnitude and direction of the resultant force F right arrow 1 + F right arrow 2. magnitude units direction counterclockwise from the +x-axis

Explanation / Answer

You have ignored the x-component, which is 5.8cos(49) = 3.805 units.

Total x component of resultant = 3.805 units
Total y component of resultant = 9.37units

You have to add these by vector addition. AS they are perpendicular, use Pythagoras:
Resultant, R = sqrt(3.805^2 + 9.37^2)

The direction to the positive x-axis is tan-1(9.37/3.805)

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